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If a line is drawn parallel to one side of the triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio. We will put in all the values of the other 3 edges and get the required value.

Let us first create the figure of the given triangle with mention of side lengths $DB = 7.2cm$, $AE = 1.8cm$ and $EC = 5.4cm$ as follows:

Now, we also have the Basic Proportionality theorem which states that If a line is drawn parallel to one side of the triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio. We will put in all the values of the other 3 edges and get the required value.

Now, in our triangle, we already have $DE||BC$ and $DE$ cuts $AB$ and $AC$ in distinct points.

So, we can apply the Basic Proportionality theorem here.

By using it, we will get:

$\dfrac{{AD}}{{DB}} = \dfrac{{AE}}{{EC}}$ ……(1)

(Because the sides are divided in same ratio)

Now, we already have the values: $DB = 7.2cm$, $AE = 1.8cm$ and $EC = 5.4cm$

Putting in all these values in (1):

$\dfrac{{AD}}{{7.2}} = \dfrac{{1.8}}{{5.4}}$

Taking 7.2 from denominator here to RHS, we will have:-

$AD = \dfrac{{1.8}}{{5.4}} \times 7.2$

Simplifying it, we get:

$AD = 2.4cm$

Hence, $AD = 2.4cm$.

The student might make the mistake of not drawing the figure first, and directly writing the fraction, which may lead to the wrong answer due to the common mistake of imagining something else. So, we must always draw the figure first before trying to solve it.

We must remember the theorem “Basic Proportionality theorem” used in the solution of this question.

Fun Fact:- The “Basic Proportionality theorem” is also known as “Thales theorem” because a famous Greek Mathematician, Thales discovered the theorem.